Question

What is the inverse function of `10=y-2x^2`?

Answer 1

`f^-1 x= sqrt((x-10)/2)`

Explanation:

Interchange x and y and solve for y

`10= x-2y^2`
`y^2= x-10`

`y=sqrt((x-10)/2)`

`f^-1 x= sqrt((x-10)/2)`