What is the derivative of # ln(cos2x)#?
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"How do you find the derivative of #y=ln(5x)#?"
1 Answer
May 9, 2018
Explanation:
#"differentiate using the "color(blue)"chain rule"#
# "given "y=f(g(x))" then"#
#dy/dx=f'(g(x))xxg'(x)larrcolor(blue)"chain rule"#
#rArrd/dx(ln(cos2x))#
#=1/(cos2x)xxd/dx(cos2x)#
#=1/(cos2x)xx-sin2x xxd/dx(2x)#
#=-2xx(sin2x)/(cos2x)=-2tan2x#
