Question

What is the derivative of `2( sinx)`?

Answer 1

`sinx` has cyclic derivatives:

`f^(n)(sinx) = cosx, -sinx, -cosx, sinx, ...`
where `f^(n)(x)` is the `n^(th)` derivative of `f(x)`.

`cosx` is `f'(x)`, `-sinx` is `f''(x)`, etc.

You can float out constants because they are just multipliers.

`d/(dx)[2sinx] = 2*d/(dx)[sinx] = 2cosx`