What is -#"2pi"/5# radians in degrees?

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Answer 1 · 2018-07-03T11:22:48

#((-2pi)/5)^R=-72^circ#

We know that,

#color(red)(pi^R=180^circ#

So,

#((-2pi)/5)^R=(180/cancelpixx(-2cancelpi)/5)^circ#

#=>((-2pi)/5)^R=(-(cancel180^36xx2)/cancel5)^circ#

#=>((-2pi)/5)^R=-72^circ#