Question

What is `lim_(x->+oo) x/(1-2x)`?

Answer 1

`lim_(x->oo)x/(1-2x)=-1/2`

Explanation:

`\ \ \ \ \ \ lim_(x->oo)x/(1-2x)`

Dividing both the numerator and denominator by `x`:
`=lim_(x->oo)1/(1/x-2)`

Now, as `x->oo`, the above limit slowly converges to `-1/2`.