How do you write #root3(125)# in exponential form?

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1 Answer
EZ as pi
Jun 2, 2016

#root3 125 = 125^(1/3)#

Explanation:

You need to be aware that roots can be written as indices (exponents).
By definition, # rootn x = x^(1/n)" " eg. sqrtx = x^(1/2)#

This is then true for any root #rArr root3 x = x^(1/3)#

In this case #root3 125 = 125^(1/3)#

This is now written in the required form, but it can be simplified
to give an answer of 5.

#root3 125 = root 3 5^3 = 5#

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