How do you write an equation in standard form for a line which passes through points (-1,-1) and (1,3)?
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"What is the chemical formula of a diamond?"
#"the equation of a line in "color(blue)"standard form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#
#"where A is a positive integer and B, C are integers"#
#"obtain the equation in "color(blue)"slope-intercept form"#
#•color(white)(x)y=mx+b#
#"where m is the slope and b the y-intercept"#
#"to calculate m use the "color(blue)"gradient formula"#
#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#
#"let "(x_1,y_1)=(-1,-1)" and "(x_2,y_2)=(1,3)#
#m=(3-(-1))/(1-(-1))=4/2=2#
#y=2x+blarrcolor(blue)"is the partial equation"#
#"to find b substitute either of the 2 given points into"#
#"the partial equation"#
#"using "(1,3)" then"#
#3=2+brArrb=3-2=1#
#y=2x+1larrcolor(red)"in slope-intercept form"#
#"rearranging gives"#
#2x-y=-1larrcolor(red)"in standard form"#
