Question

How do you solve `csc50º = y/12`?

Answer 1

`y~~15.66`

Explanation:

Here,

`csc50^color(red)circ=y/12`

`=>y=12csc50^circ`

`=>y=12/(sin50^circ)...to[becausecsctheta=1/sintheta]`

`=>y~~15.66`