How do you solve #4tantheta+2=2tantheta# in the interval #0<=x<=2pi#?

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Answer 1 · 2016-08-18T14:41:53

#theta=(3pi)/4#

#theta=(7pi)/4#

#4tan theta+2=2tan theta#

or

#4tantheta-2tan theta=-2#

or

#2tan theta=-2#

or

#tan theta=-1#

or

#tan theta=tan ((3pi)/4)#

or

#theta=(3pi)/4#-------------------------Ans #1#

Similarly for other values

#tan theta=-1#

or

#tan theta= tan((7pi)/4)#

or

#theta=(7pi)/4#---------------------------Ans #2#