How do you multiply #(x + 5y)^3#?

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Answer 1 · 2018-06-29T00:36:13

#x^3+15x^2y+75xy^2+125y^3#

Given: #(x+5y)^3#.

Use the fact that #(a+b)^3=a^3+3a^2b+3ab^2+b^3#.

Letting #a=x,b=5y#, we get:

#=x^3+3*x^2*5y+3*x*(5y)^2+(5y)^3#

#=x^3+15x^2y+3x*25y^2+125y^3#

#=x^3+15x^2y+75xy^2+125y^3#