How do you integrate #cos(5x)dx#?

↳Redirected from "How do you know a limit does not exist?"

Mar 26, 2018

Let #u = 5x#. Then #du = 5dx# and #dx= (du)/5#.

#I = int 1/5cos(u) du#

#I = 1/5sin(u) + C#

#I = 1/5sin(5x) + C#

Hopefully this helps!

22111 views around the world

You can reuse this answer
Creative Commons License