Question

How do you implicitly differentiate `-1=-y^2x-2xy+3x^2y`?

Answer 1

`dy/dx= (y^2 +2y -6xy)/(3x^2 -2x-2xy)`

Explanation:

Differentiate all terms w.r.t x one by one

0=`-y^2 -x2ydy/dx -2y -2xdy/dx + 6xy +3x^2 dy/dx`

`(-2xy- 2x +3x^2) dy/dx= y^2 +2y-6xy`

`dy/dx= (y^2 +2y -6xy)/(3x^2 -2x-2xy)`