Question

How do you graph `y=sqrt(x + 2)`?

Answer 1

See below:

Explanation:

For the equation:

`y=sqrt(x+2)`

we can graph this starting with an understanding of the graph, `sqrtx` and adjusting from there. Let's take a look at that graph first:

graph{sqrtx [-1, 10, -3, 5]}

The graph of `sqrtx` starts at `x=0, y=0` (since we're graphing in real numbers on the x and y axis, the value under the square root sign can't be negative) then passes through `x=1, y=1` and `x=4, y=2` and will head off to infinity.

So how do we now graph `sqrt(x+2)`? What will make the value under the square root sign equal 0? `x=-2`. And so the we'll have the same shape of graph, but moved 2 places to the left. It'll look like this:

graph{sqrt(x+2) [-3, 10, -3, 5]}