How do you find the midpoint of (-9,-6) (6,6)?

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Answer 1 · 2016-03-15T22:08:06

#=>P_("mid")->(x,y)->(-3/2,0)#

Important fact: The mid point on a slope lines up with the mid point of its projection onto an axis.

Thus:

Let #P_1->(x_1,y_1)->(-9,-6)#

Let #P_2->(x_2,y_2)->(6,6)#

Mid point is #(P_1+P_2)/2 -> (x_1+x_2)/2,(y_1+y_2)/2#

#P_("mid x")->(-9+6)/2 =-3/2 #

#P_("mid y")->(-6+6)/2 =0#

#=>P_("mid")->(x,y)->(-3/2,0)#