Question

How do you find the derivative of `(x-3) /( 2x+1)`?

Answer 1

`d/dx ( (x-3)/(2x+1)) = 7/(2x+1)^2`

Explanation:

Using the quotient rule:

`d/dx ( (x-3)/(2x+1)) = ( (2x+1) d/dx (x-3) - (x-3)d/dx (2x+1))/(2x+1)^2`

`d/dx ( (x-3)/(2x+1)) = ( (2x+1) - 2(x-3))/(2x+1)^2`

`d/dx ( (x-3)/(2x+1)) = ( 2x+1- 2x+6)/(2x+1)^2`

`d/dx ( (x-3)/(2x+1)) = 7/(2x+1)^2`