Question

How do you find `dx/dy` given `y=sinx+cosx`?

Answer 1

`dx/dy = 1/(cosx-sinx)`

Explanation:

`y=sinx+cosx`
`:. dy/dx = cosx-sinx`

By the chain rule `dx/dy = 1/(dy/dx)`

`:. dx/dy = 1/(cosx-sinx)`