How do you find all zeros for #(x + 1)(x - 4)(x^2 - 7)#?
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"How many antibonding orbitals are there in Benzene?"
1 Answer
Apr 17, 2018
Explanation:
#"to find the zeros equate the product of factors to zero"#
#rArr(x+1)(x-4)(x^2-7)=0#
#"equate each factor to zero and solve for x"#
#x+1=0rArrx=-1#
#x-4=0rArrx=4#
#x^2-7=0rArrx^2=7rArrx=+-sqrt7#
