How do you find a standard form equation for the line with (−1, −3); perpendicular to the line 2x + 7y + 5 = 0?

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Answer 1 · 2017-03-11T18:47:12

#(y + 3) = 7/2(x + 1)#

The slope of the given equation graphs out to be #-2/7# after switching some things around in the equation

#2x + 7y +5 = 0#

#y = -2/7x - 5/7#

The slope of the perpendicular line is the negative reciprocal of this slope

#m = - 1/(-2/7) = 7/2#

Next, you would substitute the given points and the slope that you found into the point-slope formula:

#(y - y_1) = m(x - x_1)#