How do you factor by grouping #3x^3+2x^2+3x+2#?

Question

↳Redirected from "Can mixtures be separated by chromatography?"

12065 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-30T08:43:10

we are given, 3#x^3# #+# 2#x^2# #+ #3#x# #+# 2

on rearrangement:

#=# 3#x^3# #+# 3#x# #+# 2#x^2# #+# 2

The first two terms have 3#x# in common and the last two terms have 2 in common:

taking out the common terms:
#=# 3#x# ( #x^2# + 1) #+# 2 ( #x^2# #+# 1)

making groups of two:
#=# (3 #x# #+# 2) ( #x^2# #+# 1 )