How do you evaluate the definite integral #int x^3 dx# from #[0,4]#?

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Answer 1 · 2017-02-09T10:44:47

The answer is #=64#

We need

#intx^ndx=x^(n+1)/(n+1)+C(n!=-1)#

Therefore,

#int_0^4x^3dx=[x^4/4]_0^4#

#=(4^4/4-0)#

#=4^3=64#