How do you evaluate #cos^-1(cos((5pi)/6))#?
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1 Answer
Jul 9, 2016
Explanation:
The
#cos^-1x# is the inverse function of cosxand
#color(red)(|bar(ul(color(white)(a/a)color(black)(cos^-1(cosx)=x)color(white)(a/a)|))#
#rArrcos^-1(cos((5pi)/6))=(5pi)/6#
