How do you convert #r= -8(cos(x)+(sin(x)) # into cartesian form?

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Answer 1 · 2016-03-23T02:03:28

#(x+4)^2+(y+4)^2=32#

#r=-8(cos x+sinx)#

#r^2=-8r(cosx+sinx)#-> multiply both sides by r

#r^2=-8rcosx-8rsinx#->distribute

#x^2+y^2=-8x-8y#->use formula #x=rcos theta, y=rsin theta#

#x^2+8x+y^2+8y=0#

#(x^2+8x+16)+(y^2+8y+16)=16+16#-> complete the square

#(x+4)^2+(y+4)^2=32#