Question

How do you convert `(2sqrt(2), pi/6)` into cartesian form?

Answer 1

The answer is `(sqrt6,sqrt2)`

Explanation:

`r=2sqrt2` and `theta=pi/6`
So `x=rcostheta`=>`x=2sqrt2*cos(pi/6)`
and`y=rsintheta`=>`y=2sqrt2sin(pi/6)`
`cos (pi/6)=sqrt3/2`
and`sin(pi/6)=1/2`
So the answer is `(2sqrt2*sqrt3/2,2sqrt2*1/2)`
=`(sqrt6,sqrt2)`