How do you combine #x/(x+2) - x/(x-2)#?

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How do you combine #x/(x+2) - x/(x-2)#?

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Answer 1 · 2015-05-20T13:05:08

Use #(x+2)(x-2)# as common denominator and so:
#x/(x+2)-x/(x-2)=(x(x-2)-x(x+2))/((x+2)(x-2))=#
#=(cancel(x^2)-2xcancel(-x^2)-2x)/((x+2)(x-2))=(-4x)/((x+2)(x-2))#

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How do you combine #x/(x+2) - x/(x-2)#?

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