Question

How do I find the derivative of `(x) = log_6x`?

Answer 1

`log_6 x = lnx/ln6`

Explanation:

`f(x) = log_6 x = lnx/ln6 = 1/ln6 * lnx`,
so

`f'(x) = 1/ln6 d/dx(lnx) = 1/ln6 * (1/x) = 1/(xln6)`