Can anyone solve this? From a 95% ethanol solution, prepare a 125 ml of a 75% ethanol solution.

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1 Answer
MeneerNask
Jul 9, 2015

We'll call the amount of 95% ethanol #x#

Explanation:

What we want:
#125ml,75%harr125*0.75ml# of pure ethanol

What we use:
#x ml,95%harrx*0.95#ml of pure ethanol

#0.95*x=125*0.75->x=(125*.75)/0.95->#

#x~~98.7ml# of the 95% stuff, and add water to 125ml

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