Question #18459

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Answer 1 · 2017-06-25T20:02:47

More of a physics question, but I don't mind!

The range of frequencies for the visible spectrum of electromagnetic radiation is #3.9# to #7.5*10^14# #Hz#.

#f propto 1/lambda#

Furthermore,

#lambda f = c#

This means that the product of a frequency and a wavelength of wave is equal to the speed of light.

#(3.0*10^8 m)/s = (4.0*10^-7m)f#
#f = 7.5*10^14#

#(3.0*10^8 m)/s = (7.6*10^-7m)f#
#f = 3.9*10^14 #