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Answer 1 · 2017-04-09T00:21:11

The new volume is 2390 L.

This is a Charles' Law problem.

Charles' Law is

#color(blue)(bar(ul(|color(white)(a/a) V_1/T_1 = V_2/T_2color(white)(a/a)|)))" "#

We can rearrange this to give

#V_2 = V_1 × T_2/T_1#

In this problem,

#V_1 = "1850 L"; T_1 =color(white)(ll) "3 °C" = "276.15 K"#
#V_2 = ?; color(white)(mmll)T_2 = "84 °C" = "357.15 K"#

∴ #V_2 = "1850 L" × (357.15 color(red)(cancel(color(black)("K"))))/(276.15 color(red)(cancel(color(black)("K")))) = "2390 L"#