How do you factor #(x+3)^3-4x-12# ?
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1 Answer
Feb 19, 2017
Explanation:
#(x+3)^3-4x-12 = (x+3)^3-4(x+3)#
#color(white)((x+3)^3-4x-12) = ((x+3)^2-4)(x+3)#
#color(white)((x+3)^3-4x-12) = (x^2+6x+9-4)(x+3)#
#color(white)((x+3)^3-4x-12) = (x^2+6x+5)(x+3)#
#color(white)((x+3)^3-4x-12) = (x+1)(x+5)(x+3)#
