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Answer 1 · 2017-01-04T19:22:22

Assuming you mean #c = 2pir# then solving for #r# gives #r = c/(2pi)#

See full explanation below.

Given #c = 2pir# we can solve for #r# by dividing each side of the equation by #color(red)(2pi)#

#c/color(red)(2pi) = (2pir)/color(red)(2pi)#

#c/color(red)(2pi) = (color(red)(cancel(color(black)(2pi)))r)/cancel(color(red)(2pi))#

#c/color(red)(2pi) = r#

#r = c/color(red)(2pi)#