Question

Question #e1818

Answer 1

Summing up the number of `sigma`-bond formed by the desired atom (here N) and the number of lone pair on it we can easily know the hybridization of it.

`"If the sum is 2 "->"hybridization"-sp`

`"If the sum is 3 "->"hybridization"-sp^2`

`"If the sum is 4 "->"hybridization"-sp^3`

`"If the sum is 5 "->"hybridization"-sp^3d`

`"If the sum is 6 "->"hybridization"-sp^3d^2`

Inspecting the Lewis structure of `H-CequivN:` we see that N-atom has one `sigma`-bond and one lone pair so sum is 2.
Hence the hybridization is sp.