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Answer 1 · 2015-11-03T12:51:59

#t=248791.2 sec = 69.1 t#

#rate=-(dA)/(dt)=k[A]^2#

Integrated rate Law:
#1/([A]_t)=k*t+1/([A]_0)#

0,249 M of A is used = #95.77%#
0.011 M of A is not used = #4.23%#

fraction of A not used: #4.23/100=1/23.64#

#[A]_t=([A]_0)/23.64#

and #t=t_(1/23.64)#

#1/(([A]_0)/23.64)=k*t_(1/23.64)+1/[A]_0#

#t_(1/23.64)=1/k(23.64/[A]_0-1/[A]_0)=1/(3.5*10^(-4))(22.64/0.260)#

#t_(1/23.64)=248791.2 sec = 69.1 t#