Question

What is y’ ? y= tan(sin x) + 1/3.412

Answer 1

`y'=(1+tan^2(sin(x))*cos(x)`

Explanation:

We are Using the chain rule

`(f(g(x))'=f'(g(x))*g'(x)` and that

`(tan(x))'=1+tan^2(x)` so we get

`y'=(1+tan^2(sin(x))*cos(x)`