How do you evaluate the integral #intx^10-6x^5+2x^3 dx#?

Question

↳Redirected from "Can mixtures be separated by chromatography?"

5648 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-28T20:00:47

#x^11/11-x^6+x^4/2+c#

#intx^ndx=x^(n+1)/(n+1)+c,x!=-1#

#int(x^10-6x^5+2x^3)dx#

#=x^11/11-(6x^6)/6+(2x^4)/4+c#

cancelling down we have

#x^11/11-x^6+x^4/2+c#