How do you solve #(17-x)/4 = -10#?

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Answer 1 · 2018-05-25T05:02:39

#x=57#

Multiply by #4# both sides

#(17-x)/4 = -10#

#(4 xx (17-x))/4 = -10 xx 4#

#cancel(4) xx (17-x)/cancel4 = -40#

#17-x =-40#

Subtract #17# both sides:

#17-17-x=-40-17#

#-x=-57#

Multiply by #-1# both sides and we get:

#x=57#