Question

How do you solve `4( c + 1) + 2c + 3( c - 1) = 37`?

Answer 1

`c=4`

Explanation:

Expand all the terms first
`4c+4+2c+3c-3=37`
Then shift all the numbers to the left
`4c+2c+3c=37+3-4`
`9c=36`
Then divide both sides by 9
`(9c)/9=36/9`
`c=4`