How do you solve #(1/1000)^(-1/3)#?

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Answer 1 · 2018-03-30T11:57:27

#10#

#(1/1000)^-(1/3)#

#=1/1000^-(1/3)#

#=1000^(1/3)#

#=root(3) 1000#

#=10#

Answer 2 · 2018-03-30T12:00:03

#(1/1000) ^(-1/3) = 10#

# (1/1000) ^(-1/3)#

# = ((1000/1)^-1)^(-1/3)#

# = 1000^(-1 xx-1/3)#

# = 1000^(1/3)#

#= (10^3)^(1/3) #

#= 10^(3xx1/3) #

#= 10#