Question

A projectile is shot from the ground at a velocity of `36 m/s` and at an angle of `(pi)/2`. How long will it take for the projectile to land?

Answer 1

Here actually the projection is done vertically upwards,so time of flight will be `T=(2u)/g` where, `u` is the velocity of projection.

Given, `u=36 ms^-1`

So, `T=(2×36)/9.8=7.35 s`