Question

How do you solve `x^2-8x=-16`?

Answer 1

`x = 4`

Explanation:

`x^2 - 8x = -16`

First, you move all the terms to the left side by adding 16 to both sides
`x^2 - 8x +16 = -16 +16`
`x^2 - 8x + 16 = 0`

Then you factor
`( x - 4 )( x - 4 ) = 0`

Simplify
`( x - 4 )^2`

Solve
`( x - 4 )^2 = 0`
`x = 4`