How do you simplify #(24a^6)/(32a^4)#?
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"Suppose that I don't have a formula for #g(x)# but I know that #g(1)
= 3# and #g'(x) = sqrt(x^2+15)# for all x. How do I use a linear approximation to estimate #g(0.9)# and #g(1.1)#?"
1 Answer
Mar 6, 2018
Like this.
Explanation:
It has been done just by cancelling by 2 until it reaches the simplest form and simplarly by
