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Question #7fb40

↳Redirected from "Can mixtures be separated by chromatography?"

1 Answer

Nov 3, 2017

18.00 m/s

Explanation:

Temperature at STP #= 0°C = 273 K#

Gas constant #R = 8.314 J/(mol K)#

Average velocity #=sqrt((2RT)/M) = sqrt((2 × 8.314 × 273) / 14) ms^-1 = 18.00 ms^-1#

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