Question

How do you write an equation of a line passing through (6, 1), perpendicular to `4y - 2 = 3x`?

Answer 1

`3y+4x=27`

Explanation:

`4y-2=3x`
`4y=3x+2`
`y=(3/4)x+(1/2)`
Slope of the line `m1=3/4`
Slope of perpendicular line `m2=-1/(m1)=-(1/(3/4))=-(4/3)`
Equation of the perpendicular line
`(y-1)=-(4/3)(x-6)`
`3y-3=-4x+24`
`3y+4x=27`