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Answer 1 · 2017-07-20T15:23:03

#P=4184W#

So let's say that the ice was at #0""^oC# to start with , and the man gets it to #1""^oC#.

So #1kcal=4184J# is equal to the power needed for #1g# of water to get hotter by #1""^oC#.

The energy that was put in the ice therefore was :

#E=60*4184J=251040J#

The power is then :

#P=E/(Δt)=251040/60=4184W#