Question

How do you solve `6x^2+84x+300=0` by completing the square?

Answer 1

`x=-7+-sqrt-1`

Explanation:

`6x^2+84x+300=0`
Dividing bothe the sides by `6` we get
`x^2+14x+50=0`
or
`x^2+2x(7)+49+1=0`
or
`x^2+2x(7)+49=-1`
or
`x^2+2x(7)+7^2=-1`
or
`(x+7)^2=-1`
or
`x+7=+-sqrt-1`
or
`x=-7+-sqrt-1`