What is the limit of # [sqrt(x^2+1)] / x # as x approaches infinity?

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Answer 1 · 2016-07-01T05:38:27

#1#

So, you have #sqrt(x^2+1)/x#

As #x# approached infinity, any constant such as the #1# here can be ignored because it is infintesimally small. Now you have

#sqrt(x^2)/x#

This is equal to

#x/x#

which is equal to #1#