Question

How do you integrate `int x sinx dx` using integration by parts?

Answer 1

`I = sin(x) - xcos(x) + c`

Explanation:

`I = intxsin(x)dx`

Say `u = x` so `du = 1` and `dv = sin(x)` so `v = -cos(x)`

`I = -xcos(x) + intcos(x)dx`
`I = sin(x) - xcos(x) + c`