Question

How do you factor the difference of two cubes `x^3-64`?

Answer 1

Excuse me if I'll be short, but there's not much to explain. The general formula states that

`a^3 - b^3 = (a- b)(a^2+ab+b^2)`

So, in your case, since `a=x` and `b=4`,

`x^3-64 = (x-4)(x^2+4x+16)`